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075a6bbef9
No existing test failed if the [`panic!()`][1] of the `println!()`
family of functions was removed, or if its message was changed.
So add such a test.
[1] 104f4300cf/library/std/src/io/stdio.rs (L1007-L1009)
45 lines
1.3 KiB
Rust
45 lines
1.3 KiB
Rust
// run-pass
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// check-run-results
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// ignore-windows
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// ignore-emscripten
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// ignore-fuchsia
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// ignore-horizon
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// ignore-android
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// normalize-stderr-test ".rs:\d+:\d+" -> ".rs:LL:CC"
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// Test what the error message looks like when `println!()` panics because of
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// `std::io::ErrorKind::BrokenPipe`
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#![feature(unix_sigpipe)]
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use std::env;
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use std::process::{Command, Stdio};
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#[unix_sigpipe = "sig_ign"]
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fn main() {
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let mut args = env::args();
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let me = args.next().unwrap();
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if let Some(arg) = args.next() {
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// More than enough iterations to fill any pipe buffer. Normally this
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// loop will end with a panic more or less immediately.
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for _ in 0..65536 * 64 {
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println!("{arg}");
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}
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unreachable!("should have panicked because of BrokenPipe");
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}
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// Set up a pipeline with a short-lived consumer and wait for it to finish.
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// This will produce the `println!()` panic message on stderr.
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let mut producer = Command::new(&me)
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.arg("this line shall appear exactly once on stdout")
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.env("RUST_BACKTRACE", "0")
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.stdout(Stdio::piped())
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.spawn()
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.unwrap();
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let mut consumer =
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Command::new("head").arg("-n1").stdin(producer.stdout.take().unwrap()).spawn().unwrap();
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consumer.wait().unwrap();
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producer.wait().unwrap();
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}
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