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fb61292105
Detect misparsed binop caused by missing semi When encountering ```rust foo() *bar = baz; ``` We currently emit potentially two errors, one for the return type of `foo` not being multiplicative by the type of `bar`, and another for `foo() * bar` not being assignable. We now check for this case and suggest adding a semicolon in the right place and emit only a single error. Fix #80446.